Home » Aptitude » Algebra » Question
  1. If   x = 3 + 2√2 and xy = 1, then the value of
    x2 + 3xy + y2
      is
    x2 − 3xy + y2
    1. 30
      31
    2. 70
      31
    3. 35
      31
    4. 37
      31
Correct Option: D

x = 3 + 2√2
⇒ xy = 1

⇒ y =
1
=
1
×
3 - 2√2
3 + 2√23 + 2√23 - 2√2

=
3 - 2√2
= 3 - 2√2
9 - 8

∴ x + y
= 3 + 2√2 + 3 - 2√2 = 6
x² + 3xy + y²
=
(x + y)² + xy
x² - 3xy + y²(x - y)² - 5xy

=
36 + 1
=
37
36 - 531



Your comments will be displayed only after manual approval.