a2 + b2 + c2 = 2 (a – b – c) – 3, then the value of

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a² + b² + c² = 2 (a – b – c) – 3, then the value of (a + b + c) is

1. 0
2. 1
3. – 1
4. 2

Correct Option: C

a² + b² + c² = 2a – 2b – 2c – 3
⇒ (a² – 2a + 1) + (b² + 2b + 1) + (c² + 2c + 1) = 0
⇒ (a – 1)² + (b + 1)² + (c + 1)² = 0
⇒ a = 1, b = –1, c = –1
∴ a + b + c = 1 – 1 – 1 = –1