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  1. If bc + ab + ca = abc, then the value of
    b + c
    		 +
    a + c
    		 +
    a + b
    		 = 1, then the value of
    a2
    		 +
    b2
    		 +
    c2
    		 is
    a2 + bcb2 + cac2 + aba2 + bcb2 + acc2 + ab
    1. 0
    2. 1
    3. – 1
    4. 2
Correct Option: D

a2 − bc
 +
b2 − ca
 +
c2 − ab
 = 1
a2 + bcb2 + cac2 + ab

⇒ 
a2 − bc
 + 1 +
b2 − ca
 + 1 +
c2 − ab
 + 1 = 4
a2 + bcb2 + cac2 + ab

⇒ 
a2 − bc + a2 + bc
 +
b2 − ca + b2 + ca
 +
c2 − ab + c2 + ab
 = 4
a2 + bcb2 + cac2 + ab

⇒ 
2a2
 +
2b2
 +
2c2
 = 4
a2 + bcb2 + cac2 + ab

⇒ 
a2
 +
b2
 +
c2
 =
4
 = 2
a2 + bcb2 + cac2 + ab2


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