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If ab = 21 and (a + b)2 = 25 then the value of a2 + b2 + 3ab is (a − b)2 4
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- 115
- 121
- 125
- 127
Correct Option: B
= | ||
(a − b)2 | 4 |
By componendo and dividendo,
= | ||
(a + b)2 − (a − b)2 | 25 − 4 |
⇒ | = | ||
4ab | 21 |
⇒ | = | ||
2 × 21 | 21 |
⇒ a2 + b2 = 2 × 29 = 58
∴ a2 + b2 + 3ab = 58 + 3 × 21
= 58 + 63 = 121