x + y = √3x – y = √2∴ (x + y)2 + (x – y)2 = 3 + 2⇒ 2 (x2 + y2) = 5 ...(i)Again,(x + y)2 – (x – y)2 = 3 – 2⇒ 4xy = 1 ...(ii)∴ (x2 + y2) = 5 × 1 = 5
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