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  1. If  
    a
    		 +
    b
    		 +
    c
    		 =
    1
    		 , then the value of
    1 − 2a1 − 2b1 − 2c2
    1
    		 +
    1
    		 +
    1
    		 is :
    1 − 2a1 − 2b1 − 2c
    1. 1
    2. 2
    3. 3
    4. 4
Correct Option: D

a
 +
b
 +
c
 =
1
1 − 2a1 − 2b1 − 2c2

⇒ 
2a
 +
2b
 +
2c
 =
2
 = 1
1 − 2a1 − 2b1 − 2c2

⇒ 
2a
 + 1 +
2b
 + 1 +
2c
 + 1 = 4
1 − 2a1 − 2b1 − 2c

⇒ 
2a + 1 − 2a
 +
2b + 1 − 2b
 +
2c + 1 − 2c
 = 4
1 − 2a1 − 2b1 − 2c

⇒ 
1
 +
1
 +
1
 = 4
1 − 2a1 − 2b1 − 2c


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