x + (3)2 + (x – 1)2= x2 + 2 × x × 3 + 32 + x2 – 2 × x × 1 + 12= x2 + 6x + 9 + x2 – 2x + 1= 2x2 + 4x + 10 = 2(x2 + 2x + 5)
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