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Aptitude miscellaneous
If
a +
1
2
= 3, then the value of
a
6
−
1
will be
a
a
6
1
3
0
2
Correct Option:
C
a +
1
2
= 3
a
⇒ a +
1
= √
3
a
On cubing both sides,
a +
1
3
= (√
3
)
3
a
⇒ a
3
+
1
+ 3
a +
1
= 3√
3
a
3
a
⇒ a
3
+
1
+ 3√
3
= 3√
3
a
3
⇒ a
3
+
1
= 3√
3
− 3√
3
= 0
a
3
∴ a
6
−
1
a
6
=
a
3
+
1
a
3
−
1
= 0
a
3
a
3
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