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  1. If   x3 +
    1
    		 = 110, then find the value of x +
    1
    		.
    x3x
    1. 2
    2. 3
    3. 4
    4. 5
Correct Option: D

a3 + b3 = (a + b)3 – 3ab (a + b)

∴  x3 +
1
 = 110
x3

⇒  x +
1
3 − 3x +
1
xx

= (5)3 – 3 × 5
⇒  x +
1
 = 5
x


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