x + y = 1 + xy (given)∴ x3 + y3 - x3.y3 = (x + y)3 – 3xy (x + y) – x3y3x3 + y3 - x3.y3 = (1 + xy)3 – 3xy (1 + xy) – x3y3x3 + y3 - x3.y3 = 1 + x3y3 + 3xy + 3x2y2 - 3xy - 3x2y2 - x3y3 = 1
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