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A and B can do a piece of work in 12 days and 15 days respectively. They began to work together but A left after 4 days. In how many more days would B alone complete the remaining work ?
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20 days 3 -
25 days 3 - 6 days
- 5 days
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Correct Option: C
Part of the work done by A and B in 4 days
= 4 | ![]() | + | ![]() | = 4 | ![]() | ![]() | |||
12 | 15 | 60 |
= 4 × | = | ||
60 | 5 |
Remaining work = 1 - | = | ||
5 | 5 |
∴ Time taken by B to complete the remaining work
= | × 15 = 6 days | |
5 |
Aliter :
Using Rule 20,
Here, m = 12, n = 15, p = 4
B alone do the works in
= | |
m |
= | |
12 |
= | = | = 6 days | ||
12 | 12 |