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A certain number of men can do a work in 40 days. If there were 8 men more, it could be finished in 10 days less. How many men were there initially?
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- 20
- 24
- 30
- 16
Correct Option: B
Number of men initially = x (let)
∴ M1 D1 = M2 D2
⇒ x × 40 = (x + 8) × 30
⇒ 4x = 3x + 24
⇒ 4x – 3x = 24
⇒ x = 24 men
Aliter : Using Rule 23,
Here, D = 40, a = 8, d = 10
Required number
| = | men | d |
| = | = 24 men | 10 |
