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A man is twice as fast as a woman and a woman is twice as fast as a boy in doing a work. If all of them, a man, a woman and a boy can finish the work in 7 days, in how many days a boy will do it alone ?
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- 49
- 7
- 6
- 42
Correct Option: A
Using Rule 11,
According to the question,
1 man ≡ 2 women ≡ 4 boys
∴ 1 man + 1 woman + 1 boy
= (4 + 2 +1) boys = 7 boys
∴ M1 D1 = M2 D2
⇒ 7 × 7 = 1 × D2
⇒ D2 = 49 days
