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3 men or 7 women can do a piece of work in 32 days. The number of days required by 7 men and 5 women to do a piece of work twice as large is
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- 19
- 21
- 27
- 36
Correct Option: B
∵ 3 men ≡ 7 women
| ∴ 7 men ≡ | 3 |
| = | women | 3 |
∴ 7 men + 5 women
| = |  | + 5 |  | women | 3 |
| = | | | women | 3 |
| = | women | 3 |
| ∴ | = | |||
| W1 | W2 |
| = | = | |||
| 1 | 3 × 2 |
| ⇒ D2 = | = 21 days | 64 |
Aliter : Using Rule 12,
Here, A = 3, B = 7, a = 32
A1 = 7, B1 = 5
Required time
| = | ||
| + | ||
| A | B |
| = | ||
| + | ||
| 3 | 7 |
| = | × 21 = | |||
| 64 | 2 |
They do the twice work in
| × 2 = 21 days | 2 |
