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A and B work together to complete the rest of a job in 7 days.However, 37/100 of the job was already done. Also, the work done by A in 5 days is equal to the work done by B in 4 days. How many days would be required by the fastest worker to complete the entire work?
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- 20
- 25
- 30
- 10
Correct Option: A
Remaining work
| = 1 – | 100 |
| = | = | |||
| 100 | 100 |
∴ Time taken by (A + B) in doing
| part of work = 7 days | 100 |
∴ Time taken by them in doing whole work
| = | × 7 | 63 |
| = | days | 9 |
Respective ratio of time taken by
A and B in doing the work = 5 : 4
| ∴ | + | = | ||||
| 4x | 5x | 100 |
| ⇒ | = | |||
| 20x | 100 |
⇒ 20x = 100 ⇒ x = 5
∴ Required time
= 4 × 5 = 20 days
