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To do a certain work, B would take time thrice as long as A and C together and C twice as long as A and B together. The three men together complete the work in 10 days. The time taken by A to complete the work separately is
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- 22 days
- 24 days
- 30 days
- 20 days
Correct Option: B
Using Rule 2 and 3,
If B does the work in 3x days, (A + C) will do the same work in xdays.
If C does that work in 2y days.(A + B) will do it in y days.
+ | = | |||||
x | 3x | 10 |
∴ | = | |||
3x | 10 |
⇒ 3x = 40
⇒ x = | 3 |
Again, | + | = | ||||
y | 2y | 10 |
⇒ | = | |||
2y | 10 |
⇒ y =15
∴ (A + B + C)’s 1 day’s work
= | 10 |
⇒ | + | + | = | |||||
A | 40 | 30 | 10 |
⇒ | = | - | - | |||||
A | 10 | 40 | 30 |
= | = | = | ||||
120 | 120 | 24 |
∴ A alone will complete the work in 24 days.