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Two workers A and B working together completed a job in 5 days. If A worked twice as efficiently as he actually did and B worked 1/3 as efficiently as he actually did, the work would have been completed in 3 days. To complete the job alone, A would require
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5 1 days 5 -
6 1 days 4 -
7 1 days 2 -
8 3 days 4
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Correct Option: B
Using Rule 2,
If A alone does the work in x days and B alone does the work in y days, then
| + | = | ...........(i) | ||||
| x | y | 5 |
| Again, | + | = | ...........(ii) | |||
| x | 3y | 3 |
By equation (ii) × 3 – (i),
| ⇒ | + | - | - | = 1 - | ||||||
| x | y | x | y | 5 |
| - | = | |||||
| x | x | 5 |
| = | = | |||
| x | 5 |
| ⇒ x = | = 6 | days | ||
| 4 | 4 |
