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If A, B and C can complete a work in 6 days. If A can work twice faster than B and thrice faster than C, then the number of days C alone can complete the work is :
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- 33 days
- 44 days
- 22 days
- 11 days
Correct Option: A
Using Rule 3,
Let time taken by A = x days
∴ Time taken by B = 2x days
Time taken by C = 3x days
According to the question,
| ⇒ | + | + | = | |||||
| x | 2x | 3x | 6 |
| ⇒ | = | |||
| 6x | 6 |
| ⇒ | = | |||
| 6x | 6 |
⇒ 6x = 6 × 11
| ⇒ x = | = 11 | 6 |
∴ Time taken by C alone = 3x
= 3 × 11 = 33 days
