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3 men and 7 women can do a job in 5 days, while 4 men and 6 women can do it in 4 days. The number of days required for a group of 10 women working together, at the same rate as before, to finish the same job is :
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- 30 days
- 36 days
- 40 days
- 20 days
Correct Option: D
3 × 5 men + 7 × 5 women
= 4 × 4 men + 6 × 4 women
⇒ 16 men – 15 men = 35 women – 24 women
∴ 1 man = 11 women
⇒ 3 men + 7 women = 40 women
∴ M1D1 = M2D2
⇒ 40 × 5 = 10 × D2
⇒ D2 = 20 days
Aliter : Using Rule 11,
Here, A1 = 3, B1 = 7, D1 = 5
A2 = 4, B2 = 6, D2 = 4
A3 = 0, B3 = 10
Required days
| = | days | |
| D1(A1B3 - A3B1) - D2(A2B3 - A3B2) |
| = | ||
| 5(3 × 10 - 0) - 4(4 × 10 - 0) |
| = | = 20 days | 150 - 160 |
