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  1. [2² + 3² + 4² + 5² + 6² +7² +8² + 9² +10² ] is equal to
    1. 385
    2. 2916
    3. 540
    4. 384
Correct Option: D

We know that ,

1² + 2² + 3² + .... + n² =
n(n + 1)(2n + 1)
6

∴ 2² + 3² + 4² + ..... + 10² = (1² + 2² + 3² + ..... + 10²) – 1
Here , n = 10
Required answer =
10(10 + 1)(2 × 10 + 1)
- 1
6

Required answer =
10 × 11 × 21
- 1 = 385 - 1 = 384
6



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