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The area (in sq. unit) of the triangle formed in the first quadrant by the line 3x + 4y = 12 is
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- 8
- 12
- 6
- 4
- 8
Correct Option: C
Putting y = 0 in the equation 3x + 4y = 12,
3x + 0 = 12 ⇒ x = 4
Co-ordinates of point B = (4, 0)
Putting x = 0 in the equation 3x + 4y = 12
0 + 4y = 12 ⇒ y = 3
∴ Co-ordinates of point A = (0, 3) ⇒ OB = 4 and OA = 3
∴ Area of ∆ OAB
= | × OB × OA | |
2 |
= | × 4 × 3 = 6 sq.units | |
2 |