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A right angled isosceles triangle is inscribed in a semi-circle of radius 7 cm. The area enclosed by the semi-circle but exterior to the triangle is
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- 14 cm²
- 28 cm²
- 44 cm²
- 68 cm²
- 14 cm²
Correct Option: B
Using Rule 1 and 14,
∠ACB = 90°
AC = CB = x cm
AB = 14 cm
From ∆ ABC
AC² + BC² = AB²
⇒ x² + x² = 142
⇒ 2x² = 14 × 14
⇒ x² = 14 × 7
⇒ x = √17 × 7 = 7√2cm
∴ Area of ∆ ABC
= | × AC × BC | |
2 |
= | × 7√2 × 7√2 = 49 sq.cm. | |
2 |
Area of semi-circle
= | = | × 7 × 7 | ||
2 | 7 × 2 |
= 77 sq. cm
∴ Area of the shaded region = 77 – 49 = 28 sq. cm
= 28 cm²