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The height of an equilateral triangle is 15 cm. The area of the triangle is
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- 50√3 sq. cm.
- 70√3 sq. cm.
- 75√3 sq. cm.
- 150√3 sq. cm.
- 50√3 sq. cm.
Correct Option: C
Using Rule 6, 
Let AB = BC = CA = 2a cm, AD ⊥ BC
AD = √AB² - BD²
= √4a² - a² = √3a
∴ √3a = 15
⇒ a = 5√3
∴ 2a = Side = 10√3cm
∴ Area of triangle
| = | × (10√3)² | |
| 4 |
= 75√3 sq. cm.
