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Eight consecutive numbers are given. If the average of the two numbers that appear in the middle is 6, then the sum of the eight given numbers is
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- 54
- 64
- 36
- 48
- 54
Correct Option: D
Let the first number be a.
∴ a + 3 + a + 4 = 2 × 6
⇒ 2a + 7 = 12
⇒ 2a = 5
⇒ a = | ||
2 |
∴ a + (a + 1) + ....... + (a + 7) = 8a + 28
Required number = 8 × | + 28 = 20 + 28 = 48 | |
2 |