The average of 5 consecutive integers starting with ‘m’

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The average of 5 consecutive integers starting with ‘m’ is n. What is the average of 6 consecutive integers starting with (m + 2) ?

1. 2n + 5
  2
2. (n +2)
3. (n + 3)
4. 2n + 9
  2

Correct Option: A

We know that ,
Sum of 5 consecutive integers = average × total number of integers
⇒ m + m + 1 + m + 2 + m + 3 + m + 4 = 5n
⇒ 5m + 10 = 5n
⇒ m + 2 = n ....(i)

Required average =	m + 2 + m + 3 + m + 4 + m + 5 + m + 6 + m + 7
	6

Required average =	6m + 27
	6

Required average =	2m + 9	=	2(n - 2) + 9	=	2n + 5
	2		2		2

By (1) [m = n -2 ]