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If the average of m numbers is n2 and that of n numbers is m2,then average of (m + n) numbers is
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- m/n
- m + n
- mn
- m – n
- m/n
Correct Option: C
The average of m numbers = n2
Total number of ‘m’ numbers = m × n²
And the average of n numbers = m2
Total number of ‘n’ numbers = n × m²
| ∴ Average of (m + n) numbers = | mn² + m²n | = | mn(n + m) | = mn |
| m + n | m + n |
