The lines 2x + y = 5 and x + 2y = 4 intersect at the point :
(1,2)
(2,1)
( 5/2 , 0)
(0,2)
Correct Option: B
2x + y = 5 ...(i) x + 2y = 4 ...(ii) By equation (i) × 2 – equation (ii), we have ⇒ x = 2 From equation (i), 2 × 2 + y = 5 ⇒ y = 5 – 4 = 1 ∴ Point of intersection = (2, 1)