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The length of the intercept of the graph of the equation 9x – 12y = 108 between the two axes is
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- 15 units
- 9 units
- 12 units
- 18 units
- 15 units
Correct Option: A
Putting x = 0 in 9x – 12y = 108,
0 –12y = 108
y = – 9 Putting y = 0 in 9x – 12y = 108
9x – 0 = 108
⇒ x = 12
∴ OA = 12, OB = 9
∴ AB = √OA² + OB²
= √12² + 9²
= √144 + 81
= √225
∴ AB = 15 units