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The area (in square units) of the triangle formed by the graphs of the equations x = 4, y = 3 and 3x + 4y = 12 ; is
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- 24
- 12
- 6
- 3
- 24
Correct Option: C
On putting x = 0 in the equation 3x + 4y = 12,
4y = 12, ⇒ y = 3
Again on putting y = 0,
3x = 12 ⇒ x = 4
∴ Area of ∆ABC = | × AC × BC = | × 3 × 4 = 6 sq. units | ||
2 | 2 |