Correct Option: D

The unit’s place will be occupied by 2 or 6 in three digit even numbers.
The remaining two places can be occupied by selecting from remaining four digits in ⁴P₂ ways

4P2 =	4!	=	4 × 3 × 2	= 12
	(4 - 2)!		2

∴ Total number of even three digit numbers = 2 × 12 = 24

Total ways = 3 × 4 × 2 = 24 ways.
{∵ Total available digits are 1, 2, 5, 6, 9.
Even digits = 2 and 6.
⇒ A can either be filled by 2 or 6
i.e. 2 ways.
B can either be filled by 4 ways
[∵ Total – digit used at A i.e. 5 – 1]}
and C can either be filled by 3 ways
[Total – digit used at A – digit used at B i.e. 5 – 1 – 1]