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What will be the equation of a line passing through the point (–4, 3) and having slope 1/2 ?
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- x – 2y + 5 = 0
- – x + 2y + 10 = 0
- x – 2y + 6 = 0
- x – 2y + 10 = 0
Correct Option: D
Let the equation of line bey – y1 = m(x – x1)
Here,
m = | ||
2 |
and x1 = – 4, y1 = 3
⇒ Equation of line be
y - 3 = | (x + 4) | |
2 |
2 y – 6 = x + 4
x – 2y + 10 = 0