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Find the equation of a line which passes through the point of intersection of lines x + 2y = 5 and x – 3y = 7 and also passes through the point (0, –1)
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- 3x – 29y + 1 = 0
- 3 x – 29y – 29 = 0
- 3x + 4y – 6 = 0
- –3x + 29y + 7 = 0
Correct Option: B
Let the equation of line be
(x + 2y – 5) + l(x – 3y – 7) = 0
As it passes through (0, –1)
∴ 0 – 2 – 5 + l (0 + 3 – 7) = 0 –7 – 4λ = 0
| λ = | ||
| 4 |
∴ Equation of line is
| ( x + 2y - 5) | ( x - 3y - 7) = 0 | |
| 4 |
⇒ 4x + 8y – 20 – 7x + 21y + 49 = 0
–3x + 29y + 29 = 0 3x – 29y – 29 = 0
