If x² – xy + y² = 2 and x4 + x²y²

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If x² – xy + y² = 2 and x⁴ + x²y² + y⁴ = 6, then the value of (x² + xy + y²) is :

1. 1
2. 12
3. 3
4. 36

Correct Option: C

x⁴ + x²y² + y⁴ = 6
⇒ (x² – xy + y²) (x² + xy + y²) = 6
⇒ 2 × (x² + xy + y²) = 6

⇒ x² + xy + y² =	6	= 3
	2