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  1. If
    a² + b²
    		 =
    b² + c²
    		 =
    c² + a²
    		 =
    1
    		 (k ≠ 0) then k = ?
    c²a²b²k
    1. 2
    2. 1
    3. 0
    4. 1/2
Correct Option: D

a² + b²
 =
b² + c²
 =
c² + a²
 =
1
c²a²b²k

⇒ c² = k (a² + b²);
a² = k (b² + c²);
b² = k (c² + a²)
∴ a² + b² + c² = k (b² + c² + c² + a² + a² + b²)
⇒ a² + b² + c² = 2k (a² + b² + c²)
⇒ 2k = 1
⇒ k =
1
2


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