If (4a – 3)² = 0, then the value of 64a³ –

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If (4a – 3)² = 0, then the value of 64a³ – 48a² + 12a + 13 is :

1. 0
2. 11
3. 22
4. 33

Correct Option: C

(4a – 3)² = 0
⇒ 4a – 3 = 0
⇒ 4a = 3
⇒ a = 3/4
∴ 64a³ – 48a² + 12a + 13

= 64 ×		3		³	- 48 ×		3		²	+ 12 ×	3	+ 13
		4					4				4

= 64 ×	27	-	48 × 9	+ 9 + 13
	64		16

= 27 – 27 + 22 = 22