If (x² – 2x + 1) = 0, then the value ofx4 + 1is :

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If (x² – 2x + 1) = 0, then the value of x⁴ + 1 is :
x⁴

1. 0
2. 1
3. 2
4. 3

Correct Option: C

x² – 2x + 1 = 0
⇒ (x – 1)² = 0
⇒ x – 1 = 0
⇒ x = 1

∴ x⁴ +	1	= 1 + 1 = 2
	x⁴