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  1. If x = 222, y = 223, z = 225 then the value of (x³ + y³ + z³ + 3xyz) is :
    1. 4590
    2. 4690
    3. 4950
    4. 4960
Correct Option: B

x³ + y³ + z³ – 3xyz

=
1
(x + y + z){(x-y)² + (y-z)² + (z-x)²}
2

=
1
(222 + 223 + 225){(222-223)² + (223-225)² + (225-222)²}
2

=
1
× 670(1 + 4 + 9)
2

=
670 × 14
= 4690
2



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