Correct Option: C
| (A + B)'s 1 day's work = | 1 | .....(i) |
8 |
| (B + C)'s 1 day's work = | 1 | .....(ii) |
6 |
| (C + A)'s 1 day's work = | 1 | .....(iii) |
10 |
On adding all three equations ,
| 2(A + B + C)'s 1 day's work = | 1 | + | 1 | + | 1 |
8 | 6 | 10 |
| 2(A + B + C)'s 1 day's work = | 15 + 20 + 12 | = | 47 | |
120 | 120 |
| ⇒ (A + B + C)'s 1 day’s work = | 47 | |
240 |
| ∴ (A + B + C) together will complete the work in | 240 | = 5 | 5 | days. |
47 | 47 |
Second method to solve this question ,Here , x = 8 , y = 6 , z = 10
| Time taken = | 2xyz | |
xy + yz + zx |
| Time taken = | 2 × 8 × 6 × 10 | |
8 × 6 + 6 × 10 + 10 × 8 |
| Time taken = | 960 | |
48 + 60 + 80 |
| Time taken = | 240 | = 5 | 5 | days. |
47 | 47 |
