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A contract is to be complete in 50 days and 105 men were set to work, each working 8 h a day. After 25 days, 2/5th of the work is finished. How many additional men be employed, so that the work may be completed on time, each man now working 9 h a day?
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- 34
- 36
- 35
- 37
- None of the above
Correct Option: C
According to the formula
M1D1T1/W1= M2D2T2/W2
Given M1 = 105 D1 = 25 T1 = 8 W1 = 2/5
Now let the additional men be N
Then, M2 = 105 + N, T2 = 9, D2 = 25 and W2 =1 - (2/5) = 3/5
On putting these value in the above formula
(105 x 25 x 8) / (2/5) = [(105 + N) x 25 x 9] / (3/5)
⇒ (105 x 8) / 2 = (105 + N) x (9/3)
⇒ 105 x 4 = (105 + N) x 3
⇒ 105 x 4 = 105 x 3 +3N
⇒ 3N = 105
∴ N = 35 men
