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  1. Find the least number which when divided by 16, 18 and 20 leaves a remainder 4 in each case, but is completely divisible by 7.
    1. 2884
    2. 2256
    3. 865
    4. 3332
    5. None of the above
Correct Option: A

LCM of 16, 18 and 20 = 720
∴ Required number = 720k + 4
Where, k is a natural number to be divisible by 7, (720 k + 4) will be a multiple of 7.
Smallest value of k = 4
∴ Required number = 720 x 4 + 4 = 2884



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