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A circular road runs rounds a circular ground. If the difference between the circumference of the outer circle and the inner circle is 66 meters, the width of the road is ?
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- 21 meters
- 10.5 meters
- 7 meters
- 5.25 meters
Correct Option: B
Let outer radius be R and inner radius be r.
Then from question
2πR - 2πr = 66
⇒ 2π (R-r) = 66
⇒ (2 x 22)/7 x (R - r) = 66
∴ (R-r) = (66 x 7) / 44
= 10.5 m
