In a triangle ABC, BC = 5 cm AC = 12 cm and AB = 13 cm.

In a triangle ABC, BC = 5 cm AC = 12 cm and AB = 13 cm. The length of a altitude drawn from B on AC is ?

∵ s= (13 + 5 + 12) / 2 cm
= 15cm

s-a = 2 cm,
s-b = 10 cm and
s-c = 3 cm

⇒ Area = √ (15 x 2 x 10 x 3 ) cm²
= 30 cm²

⇒ (12 x h) / 2 = 30
∴ h = 5 cm