Ⅰ. 24x2 + 38x + 15 = 0Ⅱ.12y2 + 28y + 15 = 0

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Direction: In this question 2 equations numbered I and II are given. You have to solve both the equations and find out the correct option.

Ⅰ. 24x² + 38x + 15 = 0
Ⅱ.12y² + 28y + 15 = 0

1. x ≤ y
2. x > y
3. x ≥ y
4. x < y
5. x = y, or Relationship between x and y cannot be established

Correct Option: C

According to question ,we can say that
From equation Ⅰ. 24x² + 38x + 15 = 0
⇒ 24x² + 20x + 18x + 15 = 0
⇒ 4x(6x + 5) + 3(6x + 5) = 0
⇒ (4x + 3)(6x + 5) = 0

∴ x = -	3	, -	5
	4		6

From equation Ⅱ.12y² + 28y + 15 = 0
⇒ 12y² + 18y + 10y + 15 = 0
⇒ 6y(2y + 3) + 5(2y + 3) = 0
⇒ (6y + 5)(2y + 3) = 0

∴ y = -	5	, -	3
	6		2

Hence, x ≥ y is correct answer .