Ⅰ. 3x2 − 20x −32 = 0Ⅱ. 2y2 − 3y − 20

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Direction: In this question 2 equations numbered I and II are given. You have to solve both the equations and find out the correct option.

Ⅰ. 3x² − 20x −32 = 0
Ⅱ. 2y² − 3y − 20 = 0

1. x < y
2. x ≤ y
3. x > y
4. Relationship between x and y cannot be established
5. x ≥ y

Correct Option: D

As per the given above question , we can say that
From equation Ⅰ. 3x² − 20x −32 = 0
⇒ 3x² − 12x − 8x – 32 = 0
⇒ 3x(x − 4) − 8(x − 4) = 0
⇒ (3x − 8)(x − 4) = 0

∴ x =	8	, 4
	3

From equation Ⅱ. 2y² − 3y − 20 = 0
⇒ 2y² − 8y + 5y − 20 = 0
⇒ 2y(y − 4) + 5(y − 4) = 0
⇒ (2y + 5)(y − 4) = 0

∴ y = 4, -	5
	2

Hence no relationship can be established.