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The equation x2 − px + q = 0, p, q ∈ R has on real root if :
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- p2 ≤ 4q
- p2 < 4q
- p2 > 4q
- None of these
Correct Option: B
According to question , we can say that
The equation x2 − px + q = 0, p, q ∈ R has no real root
On comparing with quadratic eq. Ax2 + Bx + C = 0 , we get
∴ A =1, B= - p, C = q
Now ,we have B2 < 4AC
⇒ ( - P )2 < 4 x 1 x q
⇒ p2 < 4q.
Hence , option B is correct answer .