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A shopkeeper buys 26 liter of milk @ Rs. 16 per liter. He also buys from another source an inferior quality of milk @ Rs. 10 per liter. How much quantity of the later should he buy to mix it with the former so that he can sell the mixture @ Rs. 14 per liter without making any loss?
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- 13 liter
- 12 liter
- 14 liter
- 16 liter
Correct Option: A
Quantity of milk @ Rs.10 per liter / Quantity of milk @ Rs. 16 per liter = 1 / 2
So, quantity of milk @ Rs. 10 per liter = 26 / 2 = 13 liter.
2nd Method
Let us assume shopkeeper buy P liter milk of price @ Rs. 10 per liter.
Buy price of 26 liter of milk @ Rs. 16 per liter = 26 x 16
Buy price of P liter of milk @ Rs. 10 per liter = P x 10
Sell price of total milk ( P + 26 ) @ Rs. 14 per liter = 14 x ( P + 26 )
According to question there is no loss or no profit.
Then Buy Price = Sell Price
26 x 16 + P x 10 = 14 x ( P + 26 )
⇒ 26 x 16 + 10P = 14P + 14 x 26
⇒ 26 x 16 - 26 x 14 = 14P - 10P
⇒ 2 x 26 = 4P
⇒ 4P = 2 x 26
⇒ P = 2 x 26 / 4 = 13
So, quantity of milk @ Rs. 10 per liter = 13 liter.
