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  1. A certain number of men can do a piece of work in 80 days. If there were 10 men less, it could be finished in 20 days more. How many men are there in the starting ?
    1. 45
    2. 50
    3. 40
    4. 60
Correct Option: B

Let the original number of men = N
Time taken by N = 80 days
Now, (N - 10) men can finish the work in the (80 + 20) = 100 days
Here, M1 = N, M2 = (N - 10), D1 = 80 and D2 = 100
According to the formula.
M1D1 = M2D2
⇒ N x 80 = 100 x (N - 10)
⇒ 8N = 10N - 100
⇒ 10N - 8N = 100
⇒ N = 50



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