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Find the number of ways of arranging the host and 8 guests at a circular table, so that the host always sits in a particular seat ?
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- 4!
- 8!
- 6!
- 9!
Correct Option: B
Total number of persons = 9
Host can sit in a particular seat in one way .
Now, remaining positions are defined relative to the host .
Hence, the remaining can sit in 8 places in 8P8 = 8! ways.
∴ The number of required arrangements = 8! x 1 = 8! = 8! ways
