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How many different numbers can be formed from the digits 3, 4, 5, 6 and 7 when repetitions are allowed ?
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- 3125
- 625
- 3905
- 125
Correct Option: C
Number of 1 digit numbers = 5
Number of 2 digit numbers = 52 = 25
Number of 3 digit numbers = 53 = 125
Number of 4 digit numbers = 54 = 625
Number of 5 digit numbers = 55 = 3125
∴ Total number of numbers formed with these digits
= 5 + 25 + 125 + 625 + 3125 = 3905