Control systems miscellaneous


Control systems miscellaneous

  1. The 3-dB bandwidth of a typical second-order system with the transfer function
    C(s)
    =
    ω2n
    R(s)s2 + 2ξ ωns + ω2n

    is given by—









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    Refer synopsis.

    Correct Option: C

    Refer synopsis.


  1. Two identical first-order systems have been cascaded non-interactively. The unit step response of the systems will be—









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    According to the equation, two identical first order systems have been cascaded non-interactively
    i.e.,
    (1 + sT) (1 + sT)
    C.E. (1 + sT) (1 + sT) = 0
    ⇒ s2T2 + 2sT + 1 = 0

    ⇒ s2 +
    2s
    +
    1
    = 0
    TT2

    2ξ ωn = 2/T
    ωn2 = 1/T2
    or
    ωn = 1/T
    ξ =
    1
    =
    1
    = 1
    nT(1/T)

    Hence alternative (D) is the correct choice.

    Correct Option: D

    According to the equation, two identical first order systems have been cascaded non-interactively
    i.e.,
    (1 + sT) (1 + sT)
    C.E. (1 + sT) (1 + sT) = 0
    ⇒ s2T2 + 2sT + 1 = 0

    ⇒ s2 +
    2s
    +
    1
    = 0
    TT2

    2ξ ωn = 2/T
    ωn2 = 1/T2
    or
    ωn = 1/T
    ξ =
    1
    =
    1
    = 1
    nT(1/T)

    Hence alternative (D) is the correct choice.



  1. An integral controller is used to improve the transient response of a first order system. If G (s) = 1/1 + s and the system is operated in closed-loop with unity feedback, what is the value of Ti if integral controller transfer function is 1/Ti s to provide damping ratio of 0.5?









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    According to question C.E. of the system 1 + G(s) H(s) = 0

    1 +
    1
    ×
    1
    = 0
    Tis1 + s

    Tis + Ti s2 + 1 = 0
    or
    s2 + s + 1/Ti = 0 …(i)
    on comparing equation (i) with the standard equation
    s2 + 2ξωn s + ωn2 = 0
    2ξωn = 1
    and
    ωn2 = 1/Ti
    or
    ωn = 1/√T2
    or
    ξ = 1/2ωn
    or
    ξ = √Ti/2
    or
    0·5 = √T1/2
    or
    Ti = 1


    Correct Option: C

    According to question C.E. of the system 1 + G(s) H(s) = 0

    1 +
    1
    ×
    1
    = 0
    Tis1 + s

    Tis + Ti s2 + 1 = 0
    or
    s2 + s + 1/Ti = 0 …(i)
    on comparing equation (i) with the standard equation
    s2 + 2ξωn s + ωn2 = 0
    2ξωn = 1
    and
    ωn2 = 1/Ti
    or
    ωn = 1/√T2
    or
    ξ = 1/2ωn
    or
    ξ = √Ti/2
    or
    0·5 = √T1/2
    or
    Ti = 1



  1. A control system is as shown in the given figure. The maximum value of gain K for which the system is stable is—











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    C(s)
    =
    K.(1/s3 + 3s2 + 2s + 1)
    R(s)1 + (1/s3 + 3s2 + 2s + 1)× 1

    and C.E = 1 + G(s) H(s)
    ⇒ + 1
    K
    . 1 = 0
    s3 + 3s2 + 2s + 1

    ⇒ s3 + 3s2 + 2s + 1 K = 0
    The Hurwitz criterion can be given as
    s3 1 2
    s2 3 1 + K
    s3 6 – (1 + K)/3 0
    s0 1 + K 0
    for the system to be stable
    6 – (1 + K)
    ≥ 0
    3

    and
    1 + K ≥ 0
    6 ≥ 1 + K
    or
    1 + K ≤ 6
    or
    K ≤ 5
    Kmax = 5


    Correct Option: D

    C(s)
    =
    K.(1/s3 + 3s2 + 2s + 1)
    R(s)1 + (1/s3 + 3s2 + 2s + 1)× 1

    and C.E = 1 + G(s) H(s)
    ⇒ + 1
    K
    . 1 = 0
    s3 + 3s2 + 2s + 1

    ⇒ s3 + 3s2 + 2s + 1 K = 0
    The Hurwitz criterion can be given as
    s3 1 2
    s2 3 1 + K
    s3 6 – (1 + K)/3 0
    s0 1 + K 0
    for the system to be stable
    6 – (1 + K)
    ≥ 0
    3

    and
    1 + K ≥ 0
    6 ≥ 1 + K
    or
    1 + K ≤ 6
    or
    K ≤ 5
    Kmax = 5




  1. The open loop transfer function of a unity feedback control system is given by:
    G(s) =
    K
    s(s + 1)

    If the gain K is increased to infinity, then the damping ratio will tend to become—









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    Given G(s) = K/s(s + 1)
    and
    H(s) = 1
    C.E. 1 + G(s) H(s) = 0

    1 +
    K
    · 1 = 0
    s(s + 1)

    s2 + s + K = 0 …(i)
    on comparing equation (i) with the standard equation
    s2 + 2ξωn s + ωn2 = 0,
    we get
    ωn2 = K
    ⇒ ωn = ± √K
    2ξωn = 1
    or ξ = 1 2√K
    Now, as K → ∞, then ξ → 0.
    Hence alternative (C) is the correct choice.

    Correct Option: C

    Given G(s) = K/s(s + 1)
    and
    H(s) = 1
    C.E. 1 + G(s) H(s) = 0

    1 +
    K
    · 1 = 0
    s(s + 1)

    s2 + s + K = 0 …(i)
    on comparing equation (i) with the standard equation
    s2 + 2ξωn s + ωn2 = 0,
    we get
    ωn2 = K
    ⇒ ωn = ± √K
    2ξωn = 1
    or ξ = 1 2√K
    Now, as K → ∞, then ξ → 0.
    Hence alternative (C) is the correct choice.